Define a class to accept values into a 3×3 array and check if it is a special array. An array
is a special array if the sum of the even elements = sum of the odd elements.
Example:
A[][]={{ 4 ,5, 6}, { 5 ,3, 2}, { 4, 2, 5}};
Sum of even elements = 4+6+2+4+2 =18
Sum of odd elements= 5+5+3+5=18
        
Solution:
,,
 



import java.util.*;
class accept
{
  public static void main(String args[])
  {
      int a[][],counteven=0,countodd=0;
      a=new int[3][3];
      Scanner sc=new Scanner(System.in);
      System.out.println("Enter the array elements");
      for(int i=0;i< 3;i++)
      {
          for(int j=0;j< 3;j++)
          {
              a[i][j]=sc.nextInt();
          }
      }

      for(int i=0;i< 3;i++)
      {
          for(int j=0;j< 3;j++)
          {
              if(a[i][j]%2==0)
              {

                  counteven+=a[i][j];
              }
              else{
                  countodd+=a[i][j];
              }
          }}

      if(counteven==countodd)
      {
          System.out.println("Special array");    
      }
      
      else{
          System.out.println("Not a Special array");  
      }
  }
}

                                                           
                                                                  


                                            



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